Howard and Vincent had some pens in the ratio of 2 : 1. Vincent and Julian had some pens in the ratio of 10 : 7. Howard sold 60 pens to Julian and ended up with half the number of pens Vincent had. How many pens did Julian have in the end?
| Howard |
Vincent |
Julian |
| 2x10 |
1x10 |
|
| |
10x1 |
7x1 |
| 20 u |
10 u |
7 u |
The number of pens that Vincent had at first is repeated. Make the number of pens that Vincent had at first the same. LCM of 1 and 10 is 10.
| |
Howard |
Vincent |
Julian |
| Before |
20 u |
10 u |
7 u |
| Change |
- 60 |
|
+ 60 |
| After |
5 u |
10 u |
7 u + 60 |
Number of pens that Howard had in the end
= 10 u ÷ 2
= 5 u
Number of pens that Howard sold to Julian
= 20 u - 5 u
= 15 u
15 u = 60
1 u = 60 ÷ 15 = 4
Number of pens that Julian had in the end
= 7 u + 60
= 7 x 4 + 60
= 28 + 60
= 88
Answer(s): 88
