Charlie and Perry had some marbles in the ratio of 3 : 2. Perry and Jenson had some marbles in the ratio of 3 : 1. Charlie sold 24 marbles to Jenson and ended up with half the number of marbles Perry had. How many marbles did Jenson have in the end?
Charlie |
Perry |
Jenson |
3x3 |
2x3 |
|
|
3x2 |
1x2 |
9 u |
6 u |
2 u |
The number of marbles that Perry had at first is repeated. Make the number of marbles that Perry had at first the same. LCM of 2 and 3 is 6.
|
Charlie |
Perry |
Jenson |
Before |
9 u |
6 u |
2 u |
Change |
- 24 |
|
+ 24 |
After |
3 u |
6 u |
2 u + 24 |
Number of marbles that Charlie had in the end
= 6 u ÷ 2
= 3 u
Number of marbles that Charlie sold to Jenson
= 9 u - 3 u
= 6 u
6 u = 24
1 u = 24 ÷ 6 = 4
Number of marbles that Jenson had in the end
= 2 u + 24
= 2 x 4 + 24
= 8 + 24
= 32
Answer(s): 32