Japheth and Cole had some pens in the ratio of 3 : 2. Cole and Bobby had some pens in the ratio of 5 : 1. Japheth sold 80 pens to Bobby and ended up with half the number of pens Cole had. How many pens did Bobby have in the end?
| Japheth |
Cole |
Bobby |
| 3x5 |
2x5 |
|
| |
5x2 |
1x2 |
| 15 u |
10 u |
2 u |
The number of pens that Cole had at first is repeated. Make the number of pens that Cole had at first the same. LCM of 2 and 5 is 10.
| |
Japheth |
Cole |
Bobby |
| Before |
15 u |
10 u |
2 u |
| Change |
- 80 |
|
+ 80 |
| After |
5 u |
10 u |
2 u + 80 |
Number of pens that Japheth had in the end
= 10 u ÷ 2
= 5 u
Number of pens that Japheth sold to Bobby
= 15 u - 5 u
= 10 u
10 u = 80
1 u = 80 ÷ 10 = 8
Number of pens that Bobby had in the end
= 2 u + 80
= 2 x 8 + 80
= 16 + 80
= 96
Answer(s): 96
