Lee and Ahmad had some marbles in the ratio of 5 : 2. Ahmad and Elijah had some marbles in the ratio of 5 : 2. Lee sold 220 marbles to Elijah and ended up with half the number of marbles Ahmad had. How many marbles did Elijah have in the end?
| Lee |
Ahmad |
Elijah |
| 5x5 |
2x5 |
|
| |
5x2 |
2x2 |
| 25 u |
10 u |
4 u |
The number of marbles that Ahmad had at first is repeated. Make the number of marbles that Ahmad had at first the same. LCM of 2 and 5 is 10.
| |
Lee |
Ahmad |
Elijah |
| Before |
25 u |
10 u |
4 u |
| Change |
- 220 |
|
+ 220 |
| After |
5 u |
10 u |
4 u + 220 |
Number of marbles that Lee had in the end
= 10 u ÷ 2
= 5 u
Number of marbles that Lee sold to Elijah
= 25 u - 5 u
= 20 u
20 u = 220
1 u = 220 ÷ 20 = 11
Number of marbles that Elijah had in the end
= 4 u + 220
= 4 x 11 + 220
= 44 + 220
= 264
Answer(s): 264
