Carl and Elijah had some buttons in the ratio of 7 : 2. Elijah and Bryan had some buttons in the ratio of 4 : 3. Carl sold 60 buttons to Bryan and ended up with half the number of buttons Elijah had. How many buttons did Bryan have in the end?
| Carl |
Elijah |
Bryan |
| 7x2 |
2x2 |
|
| |
4x1 |
3x1 |
| 14 u |
4 u |
3 u |
The number of buttons that Elijah had at first is repeated. Make the number of buttons that Elijah had at first the same. LCM of 2 and 4 is 4.
| |
Carl |
Elijah |
Bryan |
| Before |
14 u |
4 u |
3 u |
| Change |
- 60 |
|
+ 60 |
| After |
2 u |
4 u |
3 u + 60 |
Number of buttons that Carl had in the end
= 4 u ÷ 2
= 2 u
Number of buttons that Carl sold to Bryan
= 14 u - 2 u
= 12 u
12 u = 60
1 u = 60 ÷ 12 = 5
Number of buttons that Bryan had in the end
= 3 u + 60
= 3 x 5 + 60
= 15 + 60
= 75
Answer(s): 75
