Julian and Jenson had some cards in the ratio of 2 : 1. Jenson and Ahmad had some cards in the ratio of 4 : 3. Julian sold 54 cards to Ahmad and ended up with half the number of cards Jenson had. How many cards did Ahmad have in the end?
| Julian |
Jenson |
Ahmad |
| 2x4 |
1x4 |
|
| |
4x1 |
3x1 |
| 8 u |
4 u |
3 u |
The number of cards that Jenson had at first is repeated. Make the number of cards that Jenson had at first the same. LCM of 1 and 4 is 4.
| |
Julian |
Jenson |
Ahmad |
| Before |
8 u |
4 u |
3 u |
| Change |
- 54 |
|
+ 54 |
| After |
2 u |
4 u |
3 u + 54 |
Number of cards that Julian had in the end
= 4 u ÷ 2
= 2 u
Number of cards that Julian sold to Ahmad
= 8 u - 2 u
= 6 u
6 u = 54
1 u = 54 ÷ 6 = 9
Number of cards that Ahmad had in the end
= 3 u + 54
= 3 x 9 + 54
= 27 + 54
= 81
Answer(s): 81
