Bryan and Luke had some beads in the ratio of 2 : 1. Luke and Jenson had some beads in the ratio of 10 : 3. Bryan sold 30 beads to Jenson and ended up with half the number of beads Luke had. How many beads did Jenson have in the end?
| Bryan |
Luke |
Jenson |
| 2x10 |
1x10 |
|
| |
10x1 |
3x1 |
| 20 u |
10 u |
3 u |
The number of beads that Luke had at first is repeated. Make the number of beads that Luke had at first the same. LCM of 1 and 10 is 10.
| |
Bryan |
Luke |
Jenson |
| Before |
20 u |
10 u |
3 u |
| Change |
- 30 |
|
+ 30 |
| After |
5 u |
10 u |
3 u + 30 |
Number of beads that Bryan had in the end
= 10 u ÷ 2
= 5 u
Number of beads that Bryan sold to Jenson
= 20 u - 5 u
= 15 u
15 u = 30
1 u = 30 ÷ 15 = 2
Number of beads that Jenson had in the end
= 3 u + 30
= 3 x 2 + 30
= 6 + 30
= 36
Answer(s): 36
