Flynn and Jenson had some pens in the ratio of 6 : 1. Jenson and Xavier had some pens in the ratio of 8 : 3. Flynn sold 264 pens to Xavier and ended up with half the number of pens Jenson had. How many pens did Xavier have in the end?
| Flynn |
Jenson |
Xavier |
| 6x8 |
1x8 |
|
| |
8x1 |
3x1 |
| 48 u |
8 u |
3 u |
The number of pens that Jenson had at first is repeated. Make the number of pens that Jenson had at first the same. LCM of 1 and 8 is 8.
| |
Flynn |
Jenson |
Xavier |
| Before |
48 u |
8 u |
3 u |
| Change |
- 264 |
|
+ 264 |
| After |
4 u |
8 u |
3 u + 264 |
Number of pens that Flynn had in the end
= 8 u ÷ 2
= 4 u
Number of pens that Flynn sold to Xavier
= 48 u - 4 u
= 44 u
44 u = 264
1 u = 264 ÷ 44 = 6
Number of pens that Xavier had in the end
= 3 u + 264
= 3 x 6 + 264
= 18 + 264
= 282
Answer(s): 282
