Japheth and Mark had some erasers in the ratio of 2 : 1. Mark and Tim had some erasers in the ratio of 4 : 3. Japheth sold 48 erasers to Tim and ended up with half the number of erasers Mark had. How many erasers did Tim have in the end?
| Japheth |
Mark |
Tim |
| 2x4 |
1x4 |
|
| |
4x1 |
3x1 |
| 8 u |
4 u |
3 u |
The number of erasers that Mark had at first is repeated. Make the number of erasers that Mark had at first the same. LCM of 1 and 4 is 4.
| |
Japheth |
Mark |
Tim |
| Before |
8 u |
4 u |
3 u |
| Change |
- 48 |
|
+ 48 |
| After |
2 u |
4 u |
3 u + 48 |
Number of erasers that Japheth had in the end
= 4 u ÷ 2
= 2 u
Number of erasers that Japheth sold to Tim
= 8 u - 2 u
= 6 u
6 u = 48
1 u = 48 ÷ 6 = 8
Number of erasers that Tim had in the end
= 3 u + 48
= 3 x 8 + 48
= 24 + 48
= 72
Answer(s): 72
