Michael and Oscar had some pens in the ratio of 6 : 1. Oscar and Ahmad had some pens in the ratio of 4 : 3. Michael sold 176 pens to Ahmad and ended up with half the number of pens Oscar had. How many pens did Ahmad have in the end?
| Michael |
Oscar |
Ahmad |
| 6x4 |
1x4 |
|
| |
4x1 |
3x1 |
| 24 u |
4 u |
3 u |
The number of pens that Oscar had at first is repeated. Make the number of pens that Oscar had at first the same. LCM of 1 and 4 is 4.
| |
Michael |
Oscar |
Ahmad |
| Before |
24 u |
4 u |
3 u |
| Change |
- 176 |
|
+ 176 |
| After |
2 u |
4 u |
3 u + 176 |
Number of pens that Michael had in the end
= 4 u ÷ 2
= 2 u
Number of pens that Michael sold to Ahmad
= 24 u - 2 u
= 22 u
22 u = 176
1 u = 176 ÷ 22 = 8
Number of pens that Ahmad had in the end
= 3 u + 176
= 3 x 8 + 176
= 24 + 176
= 200
Answer(s): 200
