John and Charlie had some buttons in the ratio of 9 : 8. Charlie and Asher had some buttons in the ratio of 4 : 3. John sold 40 buttons to Asher and ended up with half the number of buttons Charlie had. How many buttons did Asher have in the end?
| John |
Charlie |
Asher |
| 9x1 |
8x1 |
|
| |
4x2 |
3x2 |
| 9 u |
8 u |
6 u |
The number of buttons that Charlie had at first is repeated. Make the number of buttons that Charlie had at first the same. LCM of 8 and 4 is 8.
| |
John |
Charlie |
Asher |
| Before |
9 u |
8 u |
6 u |
| Change |
- 40 |
|
+ 40 |
| After |
4 u |
8 u |
6 u + 40 |
Number of buttons that John had in the end
= 8 u ÷ 2
= 4 u
Number of buttons that John sold to Asher
= 9 u - 4 u
= 5 u
5 u = 40
1 u = 40 ÷ 5 = 8
Number of buttons that Asher had in the end
= 6 u + 40
= 6 x 8 + 40
= 48 + 40
= 88
Answer(s): 88
