Harry and David had some beads in the ratio of 7 : 6. David and Liam had some beads in the ratio of 3 : 1. Harry sold 36 beads to Liam and ended up with half the number of beads David had. How many beads did Liam have in the end?
| Harry |
David |
Liam |
| 7x1 |
6x1 |
|
| |
3x2 |
1x2 |
| 7 u |
6 u |
2 u |
The number of beads that David had at first is repeated. Make the number of beads that David had at first the same. LCM of 6 and 3 is 6.
| |
Harry |
David |
Liam |
| Before |
7 u |
6 u |
2 u |
| Change |
- 36 |
|
+ 36 |
| After |
3 u |
6 u |
2 u + 36 |
Number of beads that Harry had in the end
= 6 u ÷ 2
= 3 u
Number of beads that Harry sold to Liam
= 7 u - 3 u
= 4 u
4 u = 36
1 u = 36 ÷ 4 = 9
Number of beads that Liam had in the end
= 2 u + 36
= 2 x 9 + 36
= 18 + 36
= 54
Answer(s): 54
