Bryan and Michael had some marbles in the ratio of 5 : 2. Michael and Wesley had some marbles in the ratio of 10 : 9. Bryan sold 160 marbles to Wesley and ended up with half the number of marbles Michael had. How many marbles did Wesley have in the end?
| Bryan |
Michael |
Wesley |
| 5x5 |
2x5 |
|
| |
10x1 |
9x1 |
| 25 u |
10 u |
9 u |
The number of marbles that Michael had at first is repeated. Make the number of marbles that Michael had at first the same. LCM of 2 and 10 is 10.
| |
Bryan |
Michael |
Wesley |
| Before |
25 u |
10 u |
9 u |
| Change |
- 160 |
|
+ 160 |
| After |
5 u |
10 u |
9 u + 160 |
Number of marbles that Bryan had in the end
= 10 u ÷ 2
= 5 u
Number of marbles that Bryan sold to Wesley
= 25 u - 5 u
= 20 u
20 u = 160
1 u = 160 ÷ 20 = 8
Number of marbles that Wesley had in the end
= 9 u + 160
= 9 x 8 + 160
= 72 + 160
= 232
Answer(s): 232
