Elijah and Cody had some coins in the ratio of 7 : 5. Cody and Ryan had some coins in the ratio of 8 : 1. Elijah sold 216 coins to Ryan and ended up with half the number of coins Cody had. How many coins did Ryan have in the end?
| Elijah |
Cody |
Ryan |
| 7x8 |
5x8 |
|
| |
8x5 |
1x5 |
| 56 u |
40 u |
5 u |
The number of coins that Cody had at first is repeated. Make the number of coins that Cody had at first the same. LCM of 5 and 8 is 40.
| |
Elijah |
Cody |
Ryan |
| Before |
56 u |
40 u |
5 u |
| Change |
- 216 |
|
+ 216 |
| After |
20 u |
40 u |
5 u + 216 |
Number of coins that Elijah had in the end
= 40 u ÷ 2
= 20 u
Number of coins that Elijah sold to Ryan
= 56 u - 20 u
= 36 u
36 u = 216
1 u = 216 ÷ 36 = 6
Number of coins that Ryan had in the end
= 5 u + 216
= 5 x 6 + 216
= 30 + 216
= 246
Answer(s): 246
