Wesley and Jeremy had some pens in the ratio of 12 : 1. Jeremy and Tommy had some pens in the ratio of 10 : 9. Wesley sold 230 pens to Tommy and ended up with half the number of pens Jeremy had. How many pens did Tommy have in the end?
| Wesley |
Jeremy |
Tommy |
| 12x10 |
1x10 |
|
| |
10x1 |
9x1 |
| 120 u |
10 u |
9 u |
The number of pens that Jeremy had at first is repeated. Make the number of pens that Jeremy had at first the same. LCM of 1 and 10 is 10.
| |
Wesley |
Jeremy |
Tommy |
| Before |
120 u |
10 u |
9 u |
| Change |
- 230 |
|
+ 230 |
| After |
5 u |
10 u |
9 u + 230 |
Number of pens that Wesley had in the end
= 10 u ÷ 2
= 5 u
Number of pens that Wesley sold to Tommy
= 120 u - 5 u
= 115 u
115 u = 230
1 u = 230 ÷ 115 = 2
Number of pens that Tommy had in the end
= 9 u + 230
= 9 x 2 + 230
= 18 + 230
= 248
Answer(s): 248
