Howard and Seth had some stickers in the ratio of 9 : 8. Seth and Zeph had some stickers in the ratio of 10 : 3. Howard sold 50 stickers to Zeph and ended up with half the number of stickers Seth had. How many stickers did Zeph have in the end?
| Howard |
Seth |
Zeph |
| 9x5 |
8x5 |
|
| |
10x4 |
3x4 |
| 45 u |
40 u |
12 u |
The number of stickers that Seth had at first is repeated. Make the number of stickers that Seth had at first the same. LCM of 8 and 10 is 40.
| |
Howard |
Seth |
Zeph |
| Before |
45 u |
40 u |
12 u |
| Change |
- 50 |
|
+ 50 |
| After |
20 u |
40 u |
12 u + 50 |
Number of stickers that Howard had in the end
= 40 u ÷ 2
= 20 u
Number of stickers that Howard sold to Zeph
= 45 u - 20 u
= 25 u
25 u = 50
1 u = 50 ÷ 25 = 2
Number of stickers that Zeph had in the end
= 12 u + 50
= 12 x 2 + 50
= 24 + 50
= 74
Answer(s): 74
