Billy and Harry had some stickers in the ratio of 3 : 1. Harry and Ivan had some stickers in the ratio of 8 : 5. Billy sold 80 stickers to Ivan and ended up with half the number of stickers Harry had. How many stickers did Ivan have in the end?
| Billy |
Harry |
Ivan |
| 3x8 |
1x8 |
|
| |
8x1 |
5x1 |
| 24 u |
8 u |
5 u |
The number of stickers that Harry had at first is repeated. Make the number of stickers that Harry had at first the same. LCM of 1 and 8 is 8.
| |
Billy |
Harry |
Ivan |
| Before |
24 u |
8 u |
5 u |
| Change |
- 80 |
|
+ 80 |
| After |
4 u |
8 u |
5 u + 80 |
Number of stickers that Billy had in the end
= 8 u ÷ 2
= 4 u
Number of stickers that Billy sold to Ivan
= 24 u - 4 u
= 20 u
20 u = 80
1 u = 80 ÷ 20 = 4
Number of stickers that Ivan had in the end
= 5 u + 80
= 5 x 4 + 80
= 20 + 80
= 100
Answer(s): 100
