Luke and Brandon had some erasers in the ratio of 11 : 6. Brandon and Cody had some erasers in the ratio of 4 : 3. Luke sold 32 erasers to Cody and ended up with half the number of erasers Brandon had. How many erasers did Cody have in the end?
Luke |
Brandon |
Cody |
11x2 |
6x2 |
|
|
4x3 |
3x3 |
22 u |
12 u |
9 u |
The number of erasers that Brandon had at first is repeated. Make the number of erasers that Brandon had at first the same. LCM of 6 and 4 is 12.
|
Luke |
Brandon |
Cody |
Before |
22 u |
12 u |
9 u |
Change |
- 32 |
|
+ 32 |
After |
6 u |
12 u |
9 u + 32 |
Number of erasers that Luke had in the end
= 12 u ÷ 2
= 6 u
Number of erasers that Luke sold to Cody
= 22 u - 6 u
= 16 u
16 u = 32
1 u = 32 ÷ 16 = 2
Number of erasers that Cody had in the end
= 9 u + 32
= 9 x 2 + 32
= 18 + 32
= 50
Answer(s): 50