Archie and Michael had some pens in the ratio of 5 : 4. Michael and Henry had some pens in the ratio of 8 : 3. Archie sold 12 pens to Henry and ended up with half the number of pens Michael had. How many pens did Henry have in the end?
| Archie |
Michael |
Henry |
| 5x2 |
4x2 |
|
| |
8x1 |
3x1 |
| 10 u |
8 u |
3 u |
The number of pens that Michael had at first is repeated. Make the number of pens that Michael had at first the same. LCM of 4 and 8 is 8.
| |
Archie |
Michael |
Henry |
| Before |
10 u |
8 u |
3 u |
| Change |
- 12 |
|
+ 12 |
| After |
4 u |
8 u |
3 u + 12 |
Number of pens that Archie had in the end
= 8 u ÷ 2
= 4 u
Number of pens that Archie sold to Henry
= 10 u - 4 u
= 6 u
6 u = 12
1 u = 12 ÷ 6 = 2
Number of pens that Henry had in the end
= 3 u + 12
= 3 x 2 + 12
= 6 + 12
= 18
Answer(s): 18
