Glen and Ken had some beads in the ratio of 9 : 2. Ken and Carl had some beads in the ratio of 9 : 5. Glen sold 720 beads to Carl and ended up with half the number of beads Ken had. How many beads did Carl have in the end?
| Glen |
Ken |
Carl |
| 9x9 |
2x9 |
|
| |
9x2 |
5x2 |
| 81 u |
18 u |
10 u |
The number of beads that Ken had at first is repeated. Make the number of beads that Ken had at first the same. LCM of 2 and 9 is 18.
| |
Glen |
Ken |
Carl |
| Before |
81 u |
18 u |
10 u |
| Change |
- 720 |
|
+ 720 |
| After |
9 u |
18 u |
10 u + 720 |
Number of beads that Glen had in the end
= 18 u ÷ 2
= 9 u
Number of beads that Glen sold to Carl
= 81 u - 9 u
= 72 u
72 u = 720
1 u = 720 ÷ 72 = 10
Number of beads that Carl had in the end
= 10 u + 720
= 10 x 10 + 720
= 100 + 720
= 820
Answer(s): 820
