Neave and Justin had some buttons in the ratio of 4 : 3. Justin and Lee had some buttons in the ratio of 4 : 1. Neave sold 80 buttons to Lee and ended up with half the number of buttons Justin had. How many buttons did Lee have in the end?
| Neave |
Justin |
Lee |
| 4x4 |
3x4 |
|
| |
4x3 |
1x3 |
| 16 u |
12 u |
3 u |
The number of buttons that Justin had at first is repeated. Make the number of buttons that Justin had at first the same. LCM of 3 and 4 is 12.
| |
Neave |
Justin |
Lee |
| Before |
16 u |
12 u |
3 u |
| Change |
- 80 |
|
+ 80 |
| After |
6 u |
12 u |
3 u + 80 |
Number of buttons that Neave had in the end
= 12 u ÷ 2
= 6 u
Number of buttons that Neave sold to Lee
= 16 u - 6 u
= 10 u
10 u = 80
1 u = 80 ÷ 10 = 8
Number of buttons that Lee had in the end
= 3 u + 80
= 3 x 8 + 80
= 24 + 80
= 104
Answer(s): 104
