Lee and Charlie had some erasers in the ratio of 7 : 6. Charlie and Caden had some erasers in the ratio of 5 : 2. Lee sold 60 erasers to Caden and ended up with half the number of erasers Charlie had. How many erasers did Caden have in the end?
| Lee |
Charlie |
Caden |
| 7x5 |
6x5 |
|
| |
5x6 |
2x6 |
| 35 u |
30 u |
12 u |
The number of erasers that Charlie had at first is repeated. Make the number of erasers that Charlie had at first the same. LCM of 6 and 5 is 30.
| |
Lee |
Charlie |
Caden |
| Before |
35 u |
30 u |
12 u |
| Change |
- 60 |
|
+ 60 |
| After |
15 u |
30 u |
12 u + 60 |
Number of erasers that Lee had in the end
= 30 u ÷ 2
= 15 u
Number of erasers that Lee sold to Caden
= 35 u - 15 u
= 20 u
20 u = 60
1 u = 60 ÷ 20 = 3
Number of erasers that Caden had in the end
= 12 u + 60
= 12 x 3 + 60
= 36 + 60
= 96
Answer(s): 96
