Valen and Luis had some stickers in the ratio of 3 : 2. Luis and Ken had some stickers in the ratio of 3 : 1. Valen sold 30 stickers to Ken and ended up with half the number of stickers Luis had. How many stickers did Ken have in the end?
Valen |
Luis |
Ken |
3x3 |
2x3 |
|
|
3x2 |
1x2 |
9 u |
6 u |
2 u |
The number of stickers that Luis had at first is repeated. Make the number of stickers that Luis had at first the same. LCM of 2 and 3 is 6.
|
Valen |
Luis |
Ken |
Before |
9 u |
6 u |
2 u |
Change |
- 30 |
|
+ 30 |
After |
3 u |
6 u |
2 u + 30 |
Number of stickers that Valen had in the end
= 6 u ÷ 2
= 3 u
Number of stickers that Valen sold to Ken
= 9 u - 3 u
= 6 u
6 u = 30
1 u = 30 ÷ 6 = 5
Number of stickers that Ken had in the end
= 2 u + 30
= 2 x 5 + 30
= 10 + 30
= 40
Answer(s): 40