Ben and Tommy had some coins in the ratio of 6 : 5. Tommy and Billy had some coins in the ratio of 8 : 7. Ben sold 56 coins to Billy and ended up with half the number of coins Tommy had. How many coins did Billy have in the end?
| Ben |
Tommy |
Billy |
| 6x8 |
5x8 |
|
| |
8x5 |
7x5 |
| 48 u |
40 u |
35 u |
The number of coins that Tommy had at first is repeated. Make the number of coins that Tommy had at first the same. LCM of 5 and 8 is 40.
| |
Ben |
Tommy |
Billy |
| Before |
48 u |
40 u |
35 u |
| Change |
- 56 |
|
+ 56 |
| After |
20 u |
40 u |
35 u + 56 |
Number of coins that Ben had in the end
= 40 u ÷ 2
= 20 u
Number of coins that Ben sold to Billy
= 48 u - 20 u
= 28 u
28 u = 56
1 u = 56 ÷ 28 = 2
Number of coins that Billy had in the end
= 35 u + 56
= 35 x 2 + 56
= 70 + 56
= 126
Answer(s): 126
