Howard and Ahmad had some stickers in the ratio of 6 : 5. Ahmad and Japheth had some stickers in the ratio of 6 : 1. Howard sold 252 stickers to Japheth and ended up with half the number of stickers Ahmad had. How many stickers did Japheth have in the end?
| Howard |
Ahmad |
Japheth |
| 6x6 |
5x6 |
|
| |
6x5 |
1x5 |
| 36 u |
30 u |
5 u |
The number of stickers that Ahmad had at first is repeated. Make the number of stickers that Ahmad had at first the same. LCM of 5 and 6 is 30.
| |
Howard |
Ahmad |
Japheth |
| Before |
36 u |
30 u |
5 u |
| Change |
- 252 |
|
+ 252 |
| After |
15 u |
30 u |
5 u + 252 |
Number of stickers that Howard had in the end
= 30 u ÷ 2
= 15 u
Number of stickers that Howard sold to Japheth
= 36 u - 15 u
= 21 u
21 u = 252
1 u = 252 ÷ 21 = 12
Number of stickers that Japheth had in the end
= 5 u + 252
= 5 x 12 + 252
= 60 + 252
= 312
Answer(s): 312
