Asher and Ian had some coins in the ratio of 8 : 7. Ian and Archie had some coins in the ratio of 2 : 1. Asher sold 18 coins to Archie and ended up with half the number of coins Ian had. How many coins did Archie have in the end?
| Asher |
Ian |
Archie |
| 8x2 |
7x2 |
|
| |
2x7 |
1x7 |
| 16 u |
14 u |
7 u |
The number of coins that Ian had at first is repeated. Make the number of coins that Ian had at first the same. LCM of 7 and 2 is 14.
| |
Asher |
Ian |
Archie |
| Before |
16 u |
14 u |
7 u |
| Change |
- 18 |
|
+ 18 |
| After |
7 u |
14 u |
7 u + 18 |
Number of coins that Asher had in the end
= 14 u ÷ 2
= 7 u
Number of coins that Asher sold to Archie
= 16 u - 7 u
= 9 u
9 u = 18
1 u = 18 ÷ 9 = 2
Number of coins that Archie had in the end
= 7 u + 18
= 7 x 2 + 18
= 14 + 18
= 32
Answer(s): 32
