Tom and Michael had some pens in the ratio of 7 : 6. Michael and George had some pens in the ratio of 2 : 1. Tom sold 24 pens to George and ended up with half the number of pens Michael had. How many pens did George have in the end?
| Tom |
Michael |
George |
| 7x1 |
6x1 |
|
| |
2x3 |
1x3 |
| 7 u |
6 u |
3 u |
The number of pens that Michael had at first is repeated. Make the number of pens that Michael had at first the same. LCM of 6 and 2 is 6.
| |
Tom |
Michael |
George |
| Before |
7 u |
6 u |
3 u |
| Change |
- 24 |
|
+ 24 |
| After |
3 u |
6 u |
3 u + 24 |
Number of pens that Tom had in the end
= 6 u ÷ 2
= 3 u
Number of pens that Tom sold to George
= 7 u - 3 u
= 4 u
4 u = 24
1 u = 24 ÷ 4 = 6
Number of pens that George had in the end
= 3 u + 24
= 3 x 6 + 24
= 18 + 24
= 42
Answer(s): 42
