Reggie and Asher had some erasers in the ratio of 3 : 1. Asher and Caden had some erasers in the ratio of 4 : 3. Reggie sold 50 erasers to Caden and ended up with half the number of erasers Asher had. How many erasers did Caden have in the end?
| Reggie |
Asher |
Caden |
| 3x4 |
1x4 |
|
| |
4x1 |
3x1 |
| 12 u |
4 u |
3 u |
The number of erasers that Asher had at first is repeated. Make the number of erasers that Asher had at first the same. LCM of 1 and 4 is 4.
| |
Reggie |
Asher |
Caden |
| Before |
12 u |
4 u |
3 u |
| Change |
- 50 |
|
+ 50 |
| After |
2 u |
4 u |
3 u + 50 |
Number of erasers that Reggie had in the end
= 4 u ÷ 2
= 2 u
Number of erasers that Reggie sold to Caden
= 12 u - 2 u
= 10 u
10 u = 50
1 u = 50 ÷ 10 = 5
Number of erasers that Caden had in the end
= 3 u + 50
= 3 x 5 + 50
= 15 + 50
= 65
Answer(s): 65
