Justin and Simon had some pens in the ratio of 7 : 6. Simon and Reggie had some pens in the ratio of 7 : 1. Justin sold 56 pens to Reggie and ended up with half the number of pens Simon had. How many pens did Reggie have in the end?
| Justin |
Simon |
Reggie |
| 7x7 |
6x7 |
|
| |
7x6 |
1x6 |
| 49 u |
42 u |
6 u |
The number of pens that Simon had at first is repeated. Make the number of pens that Simon had at first the same. LCM of 6 and 7 is 42.
| |
Justin |
Simon |
Reggie |
| Before |
49 u |
42 u |
6 u |
| Change |
- 56 |
|
+ 56 |
| After |
21 u |
42 u |
6 u + 56 |
Number of pens that Justin had in the end
= 42 u ÷ 2
= 21 u
Number of pens that Justin sold to Reggie
= 49 u - 21 u
= 28 u
28 u = 56
1 u = 56 ÷ 28 = 2
Number of pens that Reggie had in the end
= 6 u + 56
= 6 x 2 + 56
= 12 + 56
= 68
Answer(s): 68
