Sean and Andy had some stickers in the ratio of 10 : 9. Andy and Jenson had some stickers in the ratio of 2 : 1. Sean sold 121 stickers to Jenson and ended up with half the number of stickers Andy had. How many stickers did Jenson have in the end?
Sean |
Andy |
Jenson |
10x2 |
9x2 |
|
|
2x9 |
1x9 |
20 u |
18 u |
9 u |
The number of stickers that Andy had at first is repeated. Make the number of stickers that Andy had at first the same. LCM of 9 and 2 is 18.
|
Sean |
Andy |
Jenson |
Before |
20 u |
18 u |
9 u |
Change |
- 121 |
|
+ 121 |
After |
9 u |
18 u |
9 u + 121 |
Number of stickers that Sean had in the end
= 18 u ÷ 2
= 9 u
Number of stickers that Sean sold to Jenson
= 20 u - 9 u
= 11 u
11 u = 121
1 u = 121 ÷ 11 = 11
Number of stickers that Jenson had in the end
= 9 u + 121
= 9 x 11 + 121
= 99 + 121
= 220
Answer(s): 220