Seth and Wesley had some buttons in the ratio of 11 : 4. Wesley and Lee had some buttons in the ratio of 10 : 3. Seth sold 495 buttons to Lee and ended up with half the number of buttons Wesley had. How many buttons did Lee have in the end?
| Seth |
Wesley |
Lee |
| 11x5 |
4x5 |
|
| |
10x2 |
3x2 |
| 55 u |
20 u |
6 u |
The number of buttons that Wesley had at first is repeated. Make the number of buttons that Wesley had at first the same. LCM of 4 and 10 is 20.
| |
Seth |
Wesley |
Lee |
| Before |
55 u |
20 u |
6 u |
| Change |
- 495 |
|
+ 495 |
| After |
10 u |
20 u |
6 u + 495 |
Number of buttons that Seth had in the end
= 20 u ÷ 2
= 10 u
Number of buttons that Seth sold to Lee
= 55 u - 10 u
= 45 u
45 u = 495
1 u = 495 ÷ 45 = 11
Number of buttons that Lee had in the end
= 6 u + 495
= 6 x 11 + 495
= 66 + 495
= 561
Answer(s): 561
