Albert, Bryan and Charlie had some marbles. Bryan had 25% less marbles than Albert. Bryan had ²₇ of Charlie's. After Albert gave 170 marbles to Bryan, he had ¹₅ of what Bryan had. How many more marbles did Charlie have than Albert in the end?

Albert	Bryan	Charlie
4x2	3x2
	2x3	7x3
8	6	21

	Charlie	Albert	Bryan	Total marbles of  Albert and Bryan
Before	21x3 = 63 u	8x3 = 24 u	6x3 = 18 u	14x3 = 42 u
Change		- 170	+ 170
After	63 u	1x7 = 7 u	5x7 = 35 u	6x7 = 42 u

Number of marbles that Bryan had less than Albert at first in percent
= 100% - 25%
= 75%

75% = ⁷⁵₁₀₀ = ³₄

Albert : Bryan = 4 : 3

The number of marbles that Bryan had at first is repeated.  Make the number of marbles that Bryan had at first the same.  LCM of 3 and 2 is 6.

When Albert gave 170 marbles to Bryan, the total number of marbles that Bryan and Albert had at first and in the end remains the same.  Make the total number of marbles that Bryan and Albert had the same.  LCM of 14 and 6 is 42.

Number of marbles that Albert gave to Bryan
= 24 u - 7 u
= 17 u

17 u = 170

1 u = 170 ÷ 17 = 10

Number of marbles that Charlie had more than Albert in the end
= 63 u - 7 u
= 56 u
= 56 x 10
= 560

Answer(s): 560