Bobby, Vincent and Tim had some marbles. Vincent had 40% more marbles than Bobby. Vincent had ²₇ of Tim's. After Bobby gave 20 marbles to Vincent, he had ¹₂ of what Vincent had. How many more marbles did Tim have than Vincent in the end?

Bobby	Vincent	Tim
5x2	7x2
	2x7	7x7
10	14	49

	Tim	Bobby	Vincent	Total marbles of  Bobby and Vincent
Before	49x1 = 49 u	10x1 = 10 u	14x1 = 14 u	24x1 = 24 u
Change		- 20	+ 20
After	49 u	1x8 = 8 u	2x8 = 16 u	3x8 = 24 u

Number of marbles that Vincent had more than Bobby at first in percent
= 100%+ 40%
= 140%

140% = ¹⁴⁰₁₀₀ = ⁷₅

Bobby : Vincent = 5 : 7

The number of marbles that Vincent had at first is repeated.  Make the number of marbles that Vincent had at first the same.  LCM of 7 and 2 is 14.

When Bobby gave 20 marbles to Vincent, the total number of marbles that Vincent and Bobby had at first and in the end remains the same.  Make the total number of marbles that Vincent and Bobby had the same.  LCM of 24 and 3 is 24.

Number of marbles that Bobby gave to Vincent
= 10 u - 8 u
= 2 u

2 u = 20

1 u = 20 ÷ 2 = 10

Number of marbles that Tim had more than Vincent in the end
= 49 u - 16 u
= 33 u
= 33 x 10
= 330

Answer(s): 330