Reggie, Ken and Zeph had some balls. Ken had 80% less balls than Reggie. Ken had ⁵₈ of Zeph's. After Reggie gave 220 balls to Ken, he had ¹₅ of what Ken had. How many more balls did Zeph have than Reggie in the end?

Reggie	Ken	Zeph
5x5	1x5
	5x1	8x1
25	5	8

	Zeph	Reggie	Ken	Total balls of  Reggie and Ken
Before	8x1 = 8 u	25x1 = 25 u	5x1 = 5 u	30x1 = 30 u
Change		- 220	+ 220
After	8 u	1x5 = 5 u	5x5 = 25 u	6x5 = 30 u

Number of balls that Ken had less than Reggie at first in percent
= 100% - 80%
= 20%

20% = ²⁰₁₀₀ = ¹₅

Reggie : Ken = 5 : 1

The number of balls that Ken had at first is repeated.  Make the number of balls that Ken had at first the same.  LCM of 1 and 5 is 5.

When Reggie gave 220 balls to Ken, the total number of balls that Ken and Reggie had at first and in the end remains the same.  Make the total number of balls that Ken and Reggie had the same.  LCM of 30 and 6 is 30.

Number of balls that Reggie gave to Ken
= 25 u - 5 u
= 20 u

20 u = 220

1 u = 220 ÷ 20 = 11

Number of balls that Zeph had more than Reggie in the end
= 8 u - 5 u
= 3 u
= 3 x 11
= 33

Answer(s): 33