Riordan, Elijah and Albert had some marbles. Elijah had 25% more marbles than Riordan. Elijah had ³₇ of Albert's. After Riordan gave 30 marbles to Elijah, he had ¹₂ of what Elijah had. How many more marbles did Albert have than Elijah in the end?

Riordan	Elijah	Albert
4x3	5x3
	3x5	7x5
12	15	35

	Albert	Riordan	Elijah	Total marbles of  Riordan and Elijah
Before	35x1 = 35 u	12x1 = 12 u	15x1 = 15 u	27x1 = 27 u
Change		- 30	+ 30
After	35 u	1x9 = 9 u	2x9 = 18 u	3x9 = 27 u

Number of marbles that Elijah had more than Riordan at first in percent
= 100%+ 25%
= 125%

125% = ¹²⁵₁₀₀ = ⁵₄

Riordan : Elijah = 4 : 5

The number of marbles that Elijah had at first is repeated.  Make the number of marbles that Elijah had at first the same.  LCM of 5 and 3 is 15.

When Riordan gave 30 marbles to Elijah, the total number of marbles that Elijah and Riordan had at first and in the end remains the same.  Make the total number of marbles that Elijah and Riordan had the same.  LCM of 27 and 3 is 27.

Number of marbles that Riordan gave to Elijah
= 12 u - 9 u
= 3 u

3 u = 30

1 u = 30 ÷ 3 = 10

Number of marbles that Albert had more than Elijah in the end
= 35 u - 18 u
= 17 u
= 17 x 10
= 170

Answer(s): 170