Glen, Lee and Gabriel had some marbles. Lee had 80% less marbles than Glen. Lee had ⁴₇ of Gabriel's. After Glen gave 84 marbles to Lee, he had ¹₂ of what Lee had. How many more marbles did Gabriel have than Glen in the end?

Glen	Lee	Gabriel
5x4	1x4
	4x1	7x1
20	4	7

	Gabriel	Glen	Lee	Total marbles of  Glen and Lee
Before	7x1 = 7 u	20x1 = 20 u	4x1 = 4 u	24x1 = 24 u
Change		- 84	+ 84
After	7 u	1x8 = 8 u	2x8 = 16 u	3x8 = 24 u

Number of marbles that Lee had less than Glen at first in percent
= 100% - 80%
= 20%

20% = ²⁰₁₀₀ = ¹₅

Glen : Lee = 5 : 1

The number of marbles that Lee had at first is repeated.  Make the number of marbles that Lee had at first the same.  LCM of 1 and 4 is 4.

When Glen gave 84 marbles to Lee, the total number of marbles that Lee and Glen had at first and in the end remains the same.  Make the total number of marbles that Lee and Glen had the same.  LCM of 24 and 3 is 24.

Number of marbles that Glen gave to Lee
= 20 u - 8 u
= 12 u

12 u = 84

1 u = 84 ÷ 12 = 7

Number of marbles that Gabriel had more than Glen in the end
= 7 u - 8 u
= -1 u
= -1 x 7
= -7

Answer(s): -7