Sam, Vaidev and Ryan had some beads. Vaidev had 80% more beads than Sam. Vaidev had ³₅ of Ryan's. After Sam gave 9 beads to Vaidev, he had ¹₂ of what Vaidev had. How many more beads did Ryan have than Vaidev in the end?

Sam	Vaidev	Ryan
5x1	9x1
	3x3	5x3
5	9	15

	Ryan	Sam	Vaidev	Total beads of  Sam and Vaidev
Before	15x3 = 45 u	5x3 = 15 u	9x3 = 27 u	14x3 = 42 u
Change		- 9	+ 9
After	45 u	1x14 = 14 u	2x14 = 28 u	3x14 = 42 u

Number of beads that Vaidev had more than Sam at first in percent
= 100%+ 80%
= 180%

180% = ¹⁸⁰₁₀₀ = ⁹₅

Sam : Vaidev = 5 : 9

The number of beads that Vaidev had at first is repeated.  Make the number of beads that Vaidev had at first the same.  LCM of 9 and 3 is 9.

When Sam gave 9 beads to Vaidev, the total number of beads that Vaidev and Sam had at first and in the end remains the same.  Make the total number of beads that Vaidev and Sam had the same.  LCM of 14 and 3 is 42.

Number of beads that Sam gave to Vaidev
= 15 u - 14 u
= 1 u

1 u = 9

1 u = 9 ÷ 1 = 9

Number of beads that Ryan had more than Vaidev in the end
= 45 u - 28 u
= 17 u
= 17 x 9
= 153

Answer(s): 153