David, Cody and Neave had some balls. Cody had 80% less balls than David. Cody had ³₈ of Neave's. After David gave 108 balls to Cody, he had ¹₂ of what Cody had. How many more balls did Neave have than David in the end?

David	Cody	Neave
5x3	1x3
	3x1	8x1
15	3	8

	Neave	David	Cody	Total balls of  David and Cody
Before	8x1 = 8 u	15x1 = 15 u	3x1 = 3 u	18x1 = 18 u
Change		- 108	+ 108
After	8 u	1x6 = 6 u	2x6 = 12 u	3x6 = 18 u

Number of balls that Cody had less than David at first in percent
= 100% - 80%
= 20%

20% = ²⁰₁₀₀ = ¹₅

David : Cody = 5 : 1

The number of balls that Cody had at first is repeated.  Make the number of balls that Cody had at first the same.  LCM of 1 and 3 is 3.

When David gave 108 balls to Cody, the total number of balls that Cody and David had at first and in the end remains the same.  Make the total number of balls that Cody and David had the same.  LCM of 18 and 3 is 18.

Number of balls that David gave to Cody
= 15 u - 6 u
= 9 u

9 u = 108

1 u = 108 ÷ 9 = 12

Number of balls that Neave had more than David in the end
= 8 u - 6 u
= 2 u
= 2 x 12
= 24

Answer(s): 24