Perry, Vaidev and Luis had some beads. Vaidev had 40% more beads than Perry. Vaidev had ⁴₇ of Luis's. After Perry gave 24 beads to Vaidev, he had ¹₂ of what Vaidev had. How many more beads did Luis have than Vaidev in the end?

Perry	Vaidev	Luis
5x4	7x4
	4x7	7x7
20	28	49

	Luis	Perry	Vaidev	Total beads of  Perry and Vaidev
Before	49x1 = 49 u	20x1 = 20 u	28x1 = 28 u	48x1 = 48 u
Change		- 24	+ 24
After	49 u	1x16 = 16 u	2x16 = 32 u	3x16 = 48 u

Number of beads that Vaidev had more than Perry at first in percent
= 100%+ 40%
= 140%

140% = ¹⁴⁰₁₀₀ = ⁷₅

Perry : Vaidev = 5 : 7

The number of beads that Vaidev had at first is repeated.  Make the number of beads that Vaidev had at first the same.  LCM of 7 and 4 is 28.

When Perry gave 24 beads to Vaidev, the total number of beads that Vaidev and Perry had at first and in the end remains the same.  Make the total number of beads that Vaidev and Perry had the same.  LCM of 48 and 3 is 48.

Number of beads that Perry gave to Vaidev
= 20 u - 16 u
= 4 u

4 u = 24

1 u = 24 ÷ 4 = 6

Number of beads that Luis had more than Vaidev in the end
= 49 u - 32 u
= 17 u
= 17 x 6
= 102

Answer(s): 102