Xavier, Mark and Julian had some beads. Mark had 40% more beads than Xavier. Mark had ²₅ of Julian's. After Xavier gave 66 beads to Mark, he had ¹₅ of what Mark had. How many more beads did Julian have than Mark in the end?

Xavier	Mark	Julian
5x2	7x2
	2x7	5x7
10	14	35

	Julian	Xavier	Mark	Total beads of  Xavier and Mark
Before	35x1 = 35 u	10x1 = 10 u	14x1 = 14 u	24x1 = 24 u
Change		- 66	+ 66
After	35 u	1x4 = 4 u	5x4 = 20 u	6x4 = 24 u

Number of beads that Mark had more than Xavier at first in percent
= 100%+ 40%
= 140%

140% = ¹⁴⁰₁₀₀ = ⁷₅

Xavier : Mark = 5 : 7

The number of beads that Mark had at first is repeated.  Make the number of beads that Mark had at first the same.  LCM of 7 and 2 is 14.

When Xavier gave 66 beads to Mark, the total number of beads that Mark and Xavier had at first and in the end remains the same.  Make the total number of beads that Mark and Xavier had the same.  LCM of 24 and 6 is 24.

Number of beads that Xavier gave to Mark
= 10 u - 4 u
= 6 u

6 u = 66

1 u = 66 ÷ 6 = 11

Number of beads that Julian had more than Mark in the end
= 35 u - 20 u
= 15 u
= 15 x 11
= 165

Answer(s): 165