Zeph, Dylan and Charlie had some marbles. Dylan had 80% less marbles than Zeph. Dylan had ⁵₈ of Charlie's. After Zeph gave 140 marbles to Dylan, he had ¹₅ of what Dylan had. How many more marbles did Charlie have than Zeph in the end?

Zeph	Dylan	Charlie
5x5	1x5
	5x1	8x1
25	5	8

	Charlie	Zeph	Dylan	Total marbles of  Zeph and Dylan
Before	8x1 = 8 u	25x1 = 25 u	5x1 = 5 u	30x1 = 30 u
Change		- 140	+ 140
After	8 u	1x5 = 5 u	5x5 = 25 u	6x5 = 30 u

Number of marbles that Dylan had less than Zeph at first in percent
= 100% - 80%
= 20%

20% = ²⁰₁₀₀ = ¹₅

Zeph : Dylan = 5 : 1

The number of marbles that Dylan had at first is repeated.  Make the number of marbles that Dylan had at first the same.  LCM of 1 and 5 is 5.

When Zeph gave 140 marbles to Dylan, the total number of marbles that Dylan and Zeph had at first and in the end remains the same.  Make the total number of marbles that Dylan and Zeph had the same.  LCM of 30 and 6 is 30.

Number of marbles that Zeph gave to Dylan
= 25 u - 5 u
= 20 u

20 u = 140

1 u = 140 ÷ 20 = 7

Number of marbles that Charlie had more than Zeph in the end
= 8 u - 5 u
= 3 u
= 3 x 7
= 21

Answer(s): 21