Neave, Ryan and Harry had some balls. Ryan had 25% more balls than Neave. Ryan had ²₅ of Harry's. After Neave gave 42 balls to Ryan, he had ¹₃ of what Ryan had. How many more balls did Harry have than Ryan in the end?

Neave	Ryan	Harry
4x2	5x2
	2x5	5x5
8	10	25

	Harry	Neave	Ryan	Total balls of  Neave and Ryan
Before	25x2 = 50 u	8x2 = 16 u	10x2 = 20 u	18x2 = 36 u
Change		- 42	+ 42
After	50 u	1x9 = 9 u	3x9 = 27 u	4x9 = 36 u

Number of balls that Ryan had more than Neave at first in percent
= 100%+ 25%
= 125%

125% = ¹²⁵₁₀₀ = ⁵₄

Neave : Ryan = 4 : 5

The number of balls that Ryan had at first is repeated.  Make the number of balls that Ryan had at first the same.  LCM of 5 and 2 is 10.

When Neave gave 42 balls to Ryan, the total number of balls that Ryan and Neave had at first and in the end remains the same.  Make the total number of balls that Ryan and Neave had the same.  LCM of 18 and 4 is 36.

Number of balls that Neave gave to Ryan
= 16 u - 9 u
= 7 u

7 u = 42

1 u = 42 ÷ 7 = 6

Number of balls that Harry had more than Ryan in the end
= 50 u - 27 u
= 23 u
= 23 x 6
= 138

Answer(s): 138