Fabian, Caden and Ahmad had some beads. Caden had 40% more beads than Fabian. Caden had ³₇ of Ahmad's. After Fabian gave 66 beads to Caden, he had ¹₃ of what Caden had. How many more beads did Ahmad have than Caden in the end?

Fabian	Caden	Ahmad
5x3	7x3
	3x7	7x7
15	21	49

	Ahmad	Fabian	Caden	Total beads of  Fabian and Caden
Before	49x1 = 49 u	15x1 = 15 u	21x1 = 21 u	36x1 = 36 u
Change		- 66	+ 66
After	49 u	1x9 = 9 u	3x9 = 27 u	4x9 = 36 u

Number of beads that Caden had more than Fabian at first in percent
= 100%+ 40%
= 140%

140% = ¹⁴⁰₁₀₀ = ⁷₅

Fabian : Caden = 5 : 7

The number of beads that Caden had at first is repeated.  Make the number of beads that Caden had at first the same.  LCM of 7 and 3 is 21.

When Fabian gave 66 beads to Caden, the total number of beads that Caden and Fabian had at first and in the end remains the same.  Make the total number of beads that Caden and Fabian had the same.  LCM of 36 and 4 is 36.

Number of beads that Fabian gave to Caden
= 15 u - 9 u
= 6 u

6 u = 66

1 u = 66 ÷ 6 = 11

Number of beads that Ahmad had more than Caden in the end
= 49 u - 27 u
= 22 u
= 22 x 11
= 242

Answer(s): 242