Howard, Eric and Jeremy had some marbles. Eric had 25% less marbles than Howard. Eric had ²₇ of Jeremy's. After Howard gave 18 marbles to Eric, he had ¹₃ of what Eric had. How many more marbles did Jeremy have than Howard in the end?

Howard	Eric	Jeremy
4x2	3x2
	2x3	7x3
8	6	21

	Jeremy	Howard	Eric	Total marbles of  Howard and Eric
Before	21x2 = 42 u	8x2 = 16 u	6x2 = 12 u	14x2 = 28 u
Change		- 18	+ 18
After	42 u	1x7 = 7 u	3x7 = 21 u	4x7 = 28 u

Number of marbles that Eric had less than Howard at first in percent
= 100% - 25%
= 75%

75% = ⁷⁵₁₀₀ = ³₄

Howard : Eric = 4 : 3

The number of marbles that Eric had at first is repeated.  Make the number of marbles that Eric had at first the same.  LCM of 3 and 2 is 6.

When Howard gave 18 marbles to Eric, the total number of marbles that Eric and Howard had at first and in the end remains the same.  Make the total number of marbles that Eric and Howard had the same.  LCM of 14 and 4 is 28.

Number of marbles that Howard gave to Eric
= 16 u - 7 u
= 9 u

9 u = 18

1 u = 18 ÷ 9 = 2

Number of marbles that Jeremy had more than Howard in the end
= 42 u - 7 u
= 35 u
= 35 x 2
= 70

Answer(s): 70