Julian, Perry and Ahmad had some balls. Perry had 25% more balls than Julian. Perry had ²₇ of Ahmad's. After Julian gave 70 balls to Perry, he had ¹₃ of what Perry had. How many more balls did Ahmad have than Perry in the end?

Julian	Perry	Ahmad
4x2	5x2
	2x5	7x5
8	10	35

	Ahmad	Julian	Perry	Total balls of  Julian and Perry
Before	35x2 = 70 u	8x2 = 16 u	10x2 = 20 u	18x2 = 36 u
Change		- 70	+ 70
After	70 u	1x9 = 9 u	3x9 = 27 u	4x9 = 36 u

Number of balls that Perry had more than Julian at first in percent
= 100%+ 25%
= 125%

125% = ¹²⁵₁₀₀ = ⁵₄

Julian : Perry = 4 : 5

The number of balls that Perry had at first is repeated.  Make the number of balls that Perry had at first the same.  LCM of 5 and 2 is 10.

When Julian gave 70 balls to Perry, the total number of balls that Perry and Julian had at first and in the end remains the same.  Make the total number of balls that Perry and Julian had the same.  LCM of 18 and 4 is 36.

Number of balls that Julian gave to Perry
= 16 u - 9 u
= 7 u

7 u = 70

1 u = 70 ÷ 7 = 10

Number of balls that Ahmad had more than Perry in the end
= 70 u - 27 u
= 43 u
= 43 x 10
= 430

Answer(s): 430