Caden, Michael and Ian had some balls. Michael had 25% more balls than Caden. Michael had ³₅ of Ian's. After Caden gave 21 balls to Michael, he had ¹₂ of what Michael had. How many more balls did Ian have than Michael in the end?

Caden	Michael	Ian
4x3	5x3
	3x5	5x5
12	15	25

	Ian	Caden	Michael	Total balls of  Caden and Michael
Before	25x1 = 25 u	12x1 = 12 u	15x1 = 15 u	27x1 = 27 u
Change		- 21	+ 21
After	25 u	1x9 = 9 u	2x9 = 18 u	3x9 = 27 u

Number of balls that Michael had more than Caden at first in percent
= 100%+ 25%
= 125%

125% = ¹²⁵₁₀₀ = ⁵₄

Caden : Michael = 4 : 5

The number of balls that Michael had at first is repeated.  Make the number of balls that Michael had at first the same.  LCM of 5 and 3 is 15.

When Caden gave 21 balls to Michael, the total number of balls that Michael and Caden had at first and in the end remains the same.  Make the total number of balls that Michael and Caden had the same.  LCM of 27 and 3 is 27.

Number of balls that Caden gave to Michael
= 12 u - 9 u
= 3 u

3 u = 21

1 u = 21 ÷ 3 = 7

Number of balls that Ian had more than Michael in the end
= 25 u - 18 u
= 7 u
= 7 x 7
= 49

Answer(s): 49