Ben, Daniel and Simon had some marbles. Daniel had 20% less marbles than Ben. Daniel had ⁵₈ of Simon's. After Ben gave 80 marbles to Daniel, he had ¹₂ of what Daniel had. How many more marbles did Simon have than Ben in the end?

Ben	Daniel	Simon
5x5	4x5
	5x4	8x4
25	20	32

	Simon	Ben	Daniel	Total marbles of  Ben and Daniel
Before	32x1 = 32 u	25x1 = 25 u	20x1 = 20 u	45x1 = 45 u
Change		- 80	+ 80
After	32 u	1x15 = 15 u	2x15 = 30 u	3x15 = 45 u

Number of marbles that Daniel had less than Ben at first in percent
= 100% - 20%
= 80%

80% = ⁸⁰₁₀₀ = ⁴₅

Ben : Daniel = 5 : 4

The number of marbles that Daniel had at first is repeated.  Make the number of marbles that Daniel had at first the same.  LCM of 4 and 5 is 20.

When Ben gave 80 marbles to Daniel, the total number of marbles that Daniel and Ben had at first and in the end remains the same.  Make the total number of marbles that Daniel and Ben had the same.  LCM of 45 and 3 is 45.

Number of marbles that Ben gave to Daniel
= 25 u - 15 u
= 10 u

10 u = 80

1 u = 80 ÷ 10 = 8

Number of marbles that Simon had more than Ben in the end
= 32 u - 15 u
= 17 u
= 17 x 8
= 136

Answer(s): 136