Eric, Ben and Zeph had some balls. Ben had 40% less balls than Eric. Ben had ⁵₈ of Zeph's. After Eric gave 187 balls to Ben, he had ¹₄ of what Ben had. How many more balls did Zeph have than Eric in the end?

Eric	Ben	Zeph
5x5	3x5
	5x3	8x3
25	15	24

	Zeph	Eric	Ben	Total balls of  Eric and Ben
Before	24x1 = 24 u	25x1 = 25 u	15x1 = 15 u	40x1 = 40 u
Change		- 187	+ 187
After	24 u	1x8 = 8 u	4x8 = 32 u	5x8 = 40 u

Number of balls that Ben had less than Eric at first in percent
= 100% - 40%
= 60%

60% = ⁶⁰₁₀₀ = ³₅

Eric : Ben = 5 : 3

The number of balls that Ben had at first is repeated.  Make the number of balls that Ben had at first the same.  LCM of 3 and 5 is 15.

When Eric gave 187 balls to Ben, the total number of balls that Ben and Eric had at first and in the end remains the same.  Make the total number of balls that Ben and Eric had the same.  LCM of 40 and 5 is 40.

Number of balls that Eric gave to Ben
= 25 u - 8 u
= 17 u

17 u = 187

1 u = 187 ÷ 17 = 11

Number of balls that Zeph had more than Eric in the end
= 24 u - 8 u
= 16 u
= 16 x 11
= 176

Answer(s): 176