Cole, Will and John had some marbles. Will had 40% more marbles than Cole. Will had ⁴₇ of John's. After Cole gave 96 marbles to Will, he had ¹₃ of what Will had. How many more marbles did John have than Will in the end?

Cole	Will	John
5x4	7x4
	4x7	7x7
20	28	49

	John	Cole	Will	Total marbles of  Cole and Will
Before	49x1 = 49 u	20x1 = 20 u	28x1 = 28 u	48x1 = 48 u
Change		- 96	+ 96
After	49 u	1x12 = 12 u	3x12 = 36 u	4x12 = 48 u

Number of marbles that Will had more than Cole at first in percent
= 100%+ 40%
= 140%

140% = ¹⁴⁰₁₀₀ = ⁷₅

Cole : Will = 5 : 7

The number of marbles that Will had at first is repeated.  Make the number of marbles that Will had at first the same.  LCM of 7 and 4 is 28.

When Cole gave 96 marbles to Will, the total number of marbles that Will and Cole had at first and in the end remains the same.  Make the total number of marbles that Will and Cole had the same.  LCM of 48 and 4 is 48.

Number of marbles that Cole gave to Will
= 20 u - 12 u
= 8 u

8 u = 96

1 u = 96 ÷ 8 = 12

Number of marbles that John had more than Will in the end
= 49 u - 36 u
= 13 u
= 13 x 12
= 156

Answer(s): 156