Will, Asher and Vaidev had some beads. Asher had 80% less beads than Will. Asher had ²₅ of Vaidev's. After Will gave 80 beads to Asher, he had ¹₅ of what Asher had. How many more beads did Vaidev have than Will in the end?

Will	Asher	Vaidev
5x2	1x2
	2x1	5x1
10	2	5

	Vaidev	Will	Asher	Total beads of  Will and Asher
Before	5x1 = 5 u	10x1 = 10 u	2x1 = 2 u	12x1 = 12 u
Change		- 80	+ 80
After	5 u	1x2 = 2 u	5x2 = 10 u	6x2 = 12 u

Number of beads that Asher had less than Will at first in percent
= 100% - 80%
= 20%

20% = ²⁰₁₀₀ = ¹₅

Will : Asher = 5 : 1

The number of beads that Asher had at first is repeated.  Make the number of beads that Asher had at first the same.  LCM of 1 and 2 is 2.

When Will gave 80 beads to Asher, the total number of beads that Asher and Will had at first and in the end remains the same.  Make the total number of beads that Asher and Will had the same.  LCM of 12 and 6 is 12.

Number of beads that Will gave to Asher
= 10 u - 2 u
= 8 u

8 u = 80

1 u = 80 ÷ 8 = 10

Number of beads that Vaidev had more than Will in the end
= 5 u - 2 u
= 3 u
= 3 x 10
= 30

Answer(s): 30